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14x-1.86x^2=14
We move all terms to the left:
14x-1.86x^2-(14)=0
a = -1.86; b = 14; c = -14;
Δ = b2-4ac
Δ = 142-4·(-1.86)·(-14)
Δ = 91.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-\sqrt{91.84}}{2*-1.86}=\frac{-14-\sqrt{91.84}}{-3.72} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+\sqrt{91.84}}{2*-1.86}=\frac{-14+\sqrt{91.84}}{-3.72} $
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